Abstract
The exponent stabilized Koopmans' theorem is used to calculate the energies of the π* anion states of 1,4,5,8-tetrahydronaphthalene. The results indicate that the ordering of π* anion states is 2 2B3g < 2 2Au < 3 2B3g. This order of anion states is the same as that which would prevail were only through-space (TS) interactions present. The through-bond (TB) interactions destabilize all the π* orbitals; however, they do not change the order.
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