Abstract
The site of attack of OH radicals on dihydrouracil and five of its methylated derivatives was determined by pulse radiolysis using N,N,N',N'-tetramethylphenylenediamine (TMPD) to detect oxidizing radicals and tetranitromethane (TNM) as well as K3Fe(CN)6 to detect reducing radicals. In the case of dihydrouracil OH radicals abstract preferentially an H atom at C(6) to give the 6-yl radical (greater than or equal to 90 per cent) which at pH approximately 6.5 reduces TNM and K3Fe(CN)6 at almost diffusion-controlled rates. Only a small fraction of OH radicals abstract the H atom at C(5) (less than or equal to 10 per cent). The resulting 5-yl radical oxidizes TMPD to TMPD+ at pH 7-8. With the methylated derivatives of dihydrouracil, OH radicals react less selectively, especially in the case of N(1)-methyl derivatives. This methyl group is activated to a similar degree as the methylene group at C(6). In 1-Medihydrouracil the yield of N(1)-CH2 radicals is about 29 per cent, which has been deduced from the yield of formaldehyde formed after oxidation of this radical by TNM at pH approximately 6.5 and the subsequent hydrolysis. Radicals at the other methyl substituents are generated to a lesser extent (less than or equal to 10 per cent) and are relatively unreactive towards oxidizing agents such as TNM and K3Fe(CN)6 as well as towards the reducing agent TMPD. Although methyl substitution opens new routes for OH attack the preferred site of H abstraction remains C(6) (greater than 60 per cent).
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