Abstract
A simple analytic formula for the free-free Gaunt factor averaged over a Maxwellian distribution is obtained by the integration of the asymptotic expansion of the classical expression for the Gaunt factor, in which the incident energy is replaced by a mean one. A comparison with the exact quantum mechanical calculation shows that the formula approximates the average free-free Gaunt factor within 1% for kT/Z2 Ryd<or=0.3 and 0.4 (kT/Z2 Ryd)32/<or= omega /Z2 Ryd<or=0.3. The average bound-free Gaunt factor is also considered.
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