Abstract

For the synthesis of metalloid tin cluster compounds applying the disproportionation reaction of a Sn(i) halide, silyl ligands, especially the symmetric Si(SiMe3)3 has proven to be extremely useful. Silyl ligands of lower symmetry where e.g. one SiMe3 group is substituted with SiPh3 are thereby unexplored, although the synthesis of the anionic silyl precursors is quite easy, referring to previously described methods. Here the synthesis of the silanide [Si(SiMe3)2(SiPh3)](-) as its potassium () as well as its lithium salt () in excellent yield is presented. proved to be a suitable starting material for the synthesis of subvalent tin compounds as shown by the reaction with tin halides in oxidation state +2 (SnCl2) and +1 (SnCl); i.e. on the one hand the anticipated stannide [Sn(Si(SiMe3)2SiPh3)2Cl](-) could be isolated and on the other hand the unexpectedly partly substituted ring compound Cl4Sn4[Si(SiMe3)2SiPh3]4 is obtained. As no elemental tin is formed during the reaction with SnCl, metalloid tin clusters may be present in solution too, which is supported by the nearly black color of the reaction mixture, showing that might be a suitable ligand for the synthesis of such cluster compounds.

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