Abstract
The reaction $^{12}C({e,e}^{\ensuremath{'}}\mathrm{pp})$ has been studied at an energy transfer $\ensuremath{\omega}\phantom{\rule{0ex}{0ex}}=\phantom{\rule{0ex}{0ex}}212\phantom{\rule{0ex}{0ex}}\mathrm{MeV}$ and a three-momentum transfer $|\mathit{q}|\phantom{\rule{0ex}{0ex}}=\phantom{\rule{0ex}{0ex}}70\phantom{\rule{0ex}{0ex}}\mathrm{MeV}/c$. The measured missing-energy spectrum shows a signature for knockout of proton pairs from $(1p{)}^{2}$, $(1p,1s)$, and $(1s{)}^{2}$ states. A comparison of the data with a calculation, in which different processes leading to two-nucleon knockout are accounted for, shows that the measured cross section for the knockout of a $(1p{)}^{2}$ pair can largely be attributed to short-range nucleon-nucleon correlations.
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