Abstract
Homonuclear multiple-quantum NMR relaxation rates for E- N-phenylformamide, whose interesting part consists of two protons A and M differently coupled to a rapidly relaxing 14N nucleus are reported. The zero- and double-quantum linewidths depend on the cross correlation spectral densities and allow the determination of 1 J and 2 J 14N- 1H spin-spin coupling constants and their relative signs. We show that the two coupling constants have the same signs and are likely to be positive. Note that only one of the resonances of the AM pair needs to be significantly broadened due to scalar interactions in order for the cross correlation spectral density to become important for the multiple-quantum relaxation rates.
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