Abstract
The kinetics of Ru(VI) catalysed oxidation of 1,5 pentane diol; 1,6-hexane-diol, 1-pentanol and 1-hexanol by hexacyanoferrate (III) ion in an aqueous alkaline medium at constant ionic strength shows zero order dependence on hexacyanoferrate (III) and first order dependence on Ru(VI) and substrate. The result suggest that a complex is formed between Ru(VI) and diol, which slowly decomposes to give a reduced form of ruthenium, which is reoxidised to Ru(VI) in a fast step be alkaline hexacyanoferrate(III). A plausible reaction mechanism is proposed.
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