Abstract

We study the Stokes eigenvalue problem under Navier boundary conditions in C^{1,1}-domains Omega subset mathbb {R}^3. Differently from the Dirichlet boundary conditions, zero may be the least eigenvalue. We fully characterize the domains where this happens and we show that the ball is the unique domain where the zero eigenvalue is not simple, it has multiplicity three. We apply these results to show the validity/failure of a suitable Poincaré-type inequality. The proofs are obtained by combining analytic and geometric arguments.

Highlights

  • Let Ω ⊂ R3 be a bounded C1,1-domain

  • To be complemented with some boundary conditions; here, ∈ R is the eigenvalue, u ∈ R3 is the eigenvector, while ∇p stands for the gradient of the pressure p of the fluid

  • (1) states that u is an eigenvector, up to the addition of a gradient. This can be functionally characterized in the framework of the Helmholtz–Weyl decomposition [11, 21], see (5)

Read more

Summary

Introduction

Let Ω ⊂ R3 be a bounded C1,1-domain. The Stokes eigenvalue problem may be written as−Δu + ∇p = u in Ω , ∇⋅u=0 in Ω , (1)to be complemented with some boundary conditions; here, ∈ R is the eigenvalue, u ∈ R3 is the eigenvector (representing the velocity of a fluid in the context of Navier–Stokes equations), while ∇p stands for the gradient of the pressure p of the fluid. Keywords Stokes eigenvalue problem · Navier boundary conditions In the zero-friction case, the homogeneous Navier boundary conditions read u ⋅ = ( u ⋅ ) ⋅ = 0 on Ω , (4)

Objectives
Results
Conclusion

Talk to us

Join us for a 30 min session where you can share your feedback and ask us any queries you have

Schedule a call

Disclaimer: All third-party content on this website/platform is and will remain the property of their respective owners and is provided on "as is" basis without any warranties, express or implied. Use of third-party content does not indicate any affiliation, sponsorship with or endorsement by them. Any references to third-party content is to identify the corresponding services and shall be considered fair use under The CopyrightLaw.