Abstract
This study presents a model, based on power generating system with shared load. The whole generating system consists of three subsystems viz: subsystem A , subsystem B and subsystem C. The subsystem A consists of one generating unit and one inbuilt transformer. The subsystem B also contains the same units and is connected in parallel to subsystem A. The output of this power system goes through the subsystem C that consists of one outer transformer and which may be further distributed as desired. The system has three types of states, viz: normal, degraded and failed. All types of failure rates and repair rates of inbuilt transformers are exponential while other repair rates are distributed quite generally. Supplementary Variable Technique has been employed to obtain various state probabilities and then the reliability parameters have been evaluated for the whole generating system.
Highlights
Electric energy demand has been rapidly increasing all over the world
The public is likely to become more and more conscious of its rights to get uninterrupted supply at proper voltage. This would force the electric supply undertakings to analyze the system and take corrective measures to improve reliability. Keeping these points in view, the author has considered a mathematical model by which the reliability of the generating system can be improved
The subsystem B, arranged in parallel with subsystem A, is a redundant system and consists of one generating unit and one inbuilt transformer. The output of these two subsystems goes through the subsystem C that consists of one outer transformer and the electric supply may be further distributed from this subsystem C as desired
Summary
P9 (s) g9 (s)P1(s) P10 (s) g10 (s)P1(s) P11(s) g11(s)P1(s) P12 (s) g12 (s)P1(s) P13 (s) g13 (s)P1(s) P14 (s) g14 (s)P1(s) P15 (s) g15 (s)P1(s) P16 (s) g16 (s)P1(s). Reliability: The reliability is given by: R (t) m1e q1t m2e q2t m3e q3t m5e q5t where,. NUMERICAL ILLUSTRATIONS Analysis of availability: Setting a 0.001, b 2 0.002, v 0.95, 1. 0.002, 1 0.001, 0.009, 0.92, 2 0.86 in the Eq 70 and taking the inverse Laplace transform, the operational availability is obtained as: Pup (t) where n1 a n3 a z1e n1t z4e n4t z2e n2t z5e n5t z3e n3t z6e n6t b. N7 a Substituting different values of t is equation (74) one may obtain Table 1 and Fig. 1. Reliability analysis: Setting a = 0.001, b = 0.002, 1 = 0.011, 2 = 0.015, = 0.05 in the Eq 72 one may obtain the variations in reliability of the system with time as shown in Table 2 and Fig. 2
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