Abstract
It was found that aromatic aldehyde, N-arylmethylenealkylamine, and formamide react together to give N-arylmethylene-1-formamido-1-arylmethylamine. Benzaldehyde and p-chlorobenzaldehyde were used as reactants with the corresponding N-arylmethylenealkylamine. By using benzaldehyde and N-(p-methoxybenzylidene) methylamine, N-(p-methoxybenzylidene)-α-formamidobenzylamines containing different aryl groups were obtained.
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