Abstract

This paper deals with reactions occurring in the aqueous system of 2-propanol/ozone. The considered reactions are discussed from thermodynamic and kinetic points of view. The major finding refers to the fact that 2-propanol reacts with O3 mainly via hydride transfer:(HO)(H3C)2CH + O3 → [(HO)(H3C)2C+ + HO3−]cage → (HO)(H3C)2C+ + HO3− → (H3C)2CO + H2O + O2Arguments supporting this proposed mechanism are: high exergonicity of reaction (ΔG = −234 kJ mol−1 for the first two steps), low HO yield - (2.4 ± 0.5)% and high acetone yield - (87.2 ± 1.5)%. Other oxidation products detected within the system are acetaldehyde - (1.4 ± 0.1)%, formaldehyde - (4.0 ± 0.1)%, acetic acid - (2.8 ± 0.2)%, formic acid - (0.6 ± 0.2)% and hydrogen peroxide - (1.5 ± 0.1)%. The temperature dependence of the second order rate constant for the reaction 2-propanol + O3 → products is ln kII = 29.64–8500 × T−1. The activation energy and pre-exponential factor derived from this relationship are (71 ± 3) kJ mol−1 and (7.5 ± 6.4) × 1012 M−1 s−1, respectively. At 23 °C, the second order rate constant is kII = (2.7 ± 0.1) M−1 s−1. The low reaction rate can be explained by the transfer of one hydride ion from 2-propanol to electrophilic ozone.

Highlights

  • This paper is one of a series that tries to shed some light on ozone reactions with compounds characterised by C–H active sites only, compounds known as less reactive

  • This study confirms the supposition that ozone reacts with 1-propanol in aqueous media mainly by hydride transfer as expected based on the results for 2-propanol/ozone aqueous system

  • In contrast to 2-propanol/ozone system, where insertion and H-abstraction have a share of a small percentage, ozone reacts with 1-propanol with yields of one order of magnitude higher as part of the afore-mentioned mechanisms

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Summary

Introduction

This paper is one of a series that tries to shed some light on ozone reactions with compounds characterised by C–H active sites only, compounds known as less reactive. Working Conditions pH = 2 t = (20 ± 0.5) ◦C pH = 7 t = 23 ◦C pH = 7 pH = 10.7 pH = 7 pH = 14

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