Abstract
Abstract The details of the reaction between vanadium trichloride oxide and hydrogen sulfide were examined at 20 and 60 °C. The main products by the reaction were vanadium dichloride oxide, sulfur, and hydrogen chloride. In addition to these products, small amounts of vanadium trichloride, vanadium tetrachloride, disulfur dichloride, and sulfur dioxide were formed. The formations of the above-mentioned reaction products can be explained as follows: The first stage is the reaction between vanadium trichloride oxide and hydrogen sulfide, 2VOCl3(1)+H2S(g)→2VOCl2(s)+S(s)+2HCl(g). Then the resulting sulfur reacts with the unreacted vanadium trichloride oxide, 2VOCl3(1)+2S(s)→2VOCl2(s)+S2Cl2(1). The resulting disulfur dichloride subsequently reacts with the unreacted vanadium trichloride oxide, 2VOCl3(1)+S2Cl2(1)→2VCl4(1)+S(s)+SO2(g). The resulting vanadium tetrachloride reacts with the sulfur formed during the reaction, 2VCl4(1)+2S(s)→2VCl3(s)+S2Cl2(1), and also reacts with hydrogen sulfide, 2VCl4(1)+H2S(g)→2VCl3(s)+S(s)+2HCl(g).
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