Abstract
·OH radicals may react with chlorpromazine in four different ways, viz.(i) electron transfer to produce the cation radical, (ii) addition to the sulphur atom followed by acid-catalysed OH– elimination to yield the cation radical, (iii) addition to the aromatic rings to produce cyclohexadienyl type radicals, and (iv) abstraction of hydrogen atoms from the —CH2— which is in the α position to the ring nitrogen. Electron transfer and addition to the sulphur atom each account for 40% of the ·OH radicals. Similar considerations apply to promazine.
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Schedule a callMore From: Journal of the Chemical Society, Faraday Transactions 1: Physical Chemistry in Condensed Phases
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