Abstract
In this work, we propose that there exists a moving triangle singularity in the $\ensuremath{\psi}(2S)\ensuremath{\rightarrow}{\ensuremath{\pi}}^{+}{\ensuremath{\pi}}^{\ensuremath{-}}{K}^{+}{K}^{\ensuremath{-}}$ process, whose position can vary from 1.158 to 1.181 GeV in the invariant mass spectrum of ${K}^{+}{K}^{\ensuremath{-}}$. After a precise analysis on this process, it turns out that after doing some cuts on ${m}_{{\ensuremath{\pi}}^{+}{\ensuremath{\pi}}^{\ensuremath{-}}}$, experiments do have the opportunity to observe this triangle singularity. In addition, when changing the cuts on ${m}_{{\ensuremath{\pi}}^{+}{\ensuremath{\pi}}^{\ensuremath{-}}}$, the movement of the predicted triangle singularity can also be observed. Thus, we suggest future experiments, especially Super Tau-Charm Facility (STCF), to do an analysis on the $\ensuremath{\psi}(2S)\ensuremath{\rightarrow}{\ensuremath{\pi}}^{+}{\ensuremath{\pi}}^{\ensuremath{-}}{K}^{+}{K}^{\ensuremath{-}}$ process to verify our prediction.
Highlights
In the past decades, the triangle singularity that proposed by L
In recent years, with the discoveries of a series of exotic states such as Zc [9–15], Pc [16,17] and X(2900) [18,19], many researches on triangle singularity have been carried out [2–6,8,20–57], which imply that these exotic states can be related to some specific triangle singularities
By using the triangle singularity produced by the kaon loop, they successfully explained the peak of a1ð1420Þ without introducing the Breit-Wigner structure
Summary
The triangle singularity that proposed by L. [59] proposed that it is very possible for experiments to detect a pure triangle singularity in the ψð2SÞ → ppη process, where the triangle loop is composed by J=ψ, η and proton. Under this situation, the position of the triangle singularity is 80 MeV above the J=ψη threshold. If we fix the value of mCD in the permitted kinematical range, due to the triangle singularity there will be a peak structure in the invariant mass spectrum of ðE; FÞ and the peak position can be solved exactly from Eqs.
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