Practical two-step synthesis of enantiopure styrene oxide through an optimized chemoenzymatic approach.

Abstract

Enantiopure styrene oxide (SO) and its derivatives are important building blocks for chiral synthesis. In this study, we developed an attractive "1-pot, 2-step" chemoenzymatic approach for producing enantiopure SO with 100% theoretical yield. This approach involved asymmetric reduction of α-chloroacetophenone by an alcohol dehydrogenase (ADH; step 1), followed by base-induced ring closure (epoxidation) of enantiopure 2-chloro-1-phenylethanol produced by the ADH (step 2). By-product formation during epoxidation was suppressed to <1% by adding methyl tert-butyl ether (MTBE) as the second phase. Therefore, with this optimized approach, ADH from Lactobacillus kefir (LkDH) successfully produced 1M (S)-SO, with 99% analytical yield and 97.8% enantiomeric excess (ee). In the preparation of (R)-SO, a semi-rational strategy of active pocket iterative saturation mutagenesis (ISM) was successfully used to inverse the enantioselectivity of LkDH (muDH2, F147L/Y190P/A202F/M206H/V196L/S96D/K97V), which produced the opposite enantiomer (R)-2-chloro-1-phenylethanol. Through the optimized chemoenzymatic approach, muDH2 was successfully used to prepare 1M (R)-SO, with 98.1% ee and 99.0% analytical yield. Our results indicated that this optimized chemoenzymatic approach could be used to produce both enantiomers of SO at concentrations as high as 120g/L within 14h, which is the highest concentration as far as we know. MuDH2 obtained through ISM also showed reversed enantioselectivity toward another 13 aromatic ketones, compared with wild-type (WT) LkDH. Furthermore, a molecular docking experiment demonstrated that muDH2 inverted the binding orientation of the substrate, which may be the reason for its inverse enantioselectivity.