Abstract
Polarizations of the phosphorescence ( T 1 → S 0) relative to the lowest π ∗ ← n and π ∗ ← π absorption have been investigated in acetophenone, benzophenone, and anthrone. The results indicate that the lowest triplet state is an ( n, π ∗ ) state, the lowest singlet state is a 1 U state, and that the lowest (π, π ∗ ) state can be described analogous to 1 L b state in aromatic hydrocarbons. The 1U ← 1A transition is allowed by the mixing of the 1 U state with (π, π ∗ ) states of A 1 symmetry. In acetophenone and benzophenone the mixing of 1 U with 1 W also contributes to the 1U ← 1A transition probability.
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