Abstract
Solubility of the quaternary system RbCl−SmCl3−HCl(12.84, 22.66 % by mass)−H2O was determined at 298.15 K, and corresponding equilibrium diagrams were constructed. The quaternary system is complicated with three equilibrium solid phases RbCl, RbSmCl4·4H2O (1:1 type), and SmCl3·6H2O. The solubilities of RbCl, RbSmCl4·4H2O, and SmCl3·6H2O decreased with an increase of the concentration of HCl. The crystallization field decreased for RbCl and SmCl3·6H2O and increased for RbSmCl4·4H2O with an increase in the HCl concentration. The new solid-phase compound RbSmCl4·4H2O was found to be uncongruently soluble in the system. The compound RbSmCl4·4H2O was characterized by the methods of X-ray diffraction, thermogravimetry, and differential thermogravimetry. The compound loses its crystal water by one step at (359 to 457) K. The standard molar enthalpy of solution of RbSmCl4·4H2O in deionized water was measured to be −(29.40 ± 0.26) kJ·mol−1 by heat conduction microcalorimetry. Its standard molar enthalpy of formation was calculated to be −(2725.3 ± 1.0) kJ·mol−1.
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