Abstract
Pb 2PtO 4 was prepared by the solid state reaction between lead monoxide and platinum metal in the appropriate ratio at 690–720°C. It decomposed to PbO and Pt at 735°C. The symmetry is orthorhombic: a = 9.115(4), b = 7.941(4), c = 6.306(4) Å, Z = 2, space group Pbam. The crystal structure was solved by conventional methods to R = 0.049 using 851 independent reflections. The structure consists of chains of edge-shared PtO 6 octahedra extending along the c-axis direction. Lead atoms are stacked in rows in the channels between the chains. The conductivity of Pb 2PtO 4 is low (σ(300 K) ⋍ 10 −5 (Ω · cm) −1), in agreement with the presence of fully oxidized tetravalent platinum.
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