Abstract
Inelastic electron-scattering form factors of magnetic states in closed-shell nuclei are calculated taking into account the combined effect of the mesonic degrees of freedom and the two-particle-two-hole components of the nuclear wave functions which come from the particle-core vibration coupling. The one-body nucleon- and two-body meson-exchange current contributions to the form factor are evaluated with the same realistic mean field. Application to various high-spin magnetic states of oxygen and lead is made. The comparison with experiment shows an excellent agreement for the states 14 −(6.74 MeV) and 12 1 −(7.06 MeV) in lead, while such is not the case for the second 12 2 −(6.43 MeV) state in lead and the 4 −(18.98MeV) state in oxygen essentially due to mixing configuration effects and the non-consideration of 3p3h excitations, respectively.
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