Abstract

Palladium(II) forms the complexes [PdL2](1)–(4) on reaction of tetrachloropalladate(II) with 6-amino-5-arylazouracil derivatives (uracil = pyrimidine-2,4-dione) in ethanolic media, with the exception of 6-amino-5-(2′-chlorophenylazo)-3-methyluracil (HL5) which leads to the complex [Pd(HL5)2Cl2](5). The crystal structure of the complex bis(6-amino-1,3-dimethyl-5-phenylazouracilato)palladium(II), [PdL12](1), was determined by X-ray crystallography. The complex crystallizes in the monoclinic system, space group P21/c, with a= 7.404(2), b= 9.537(1), c= 17.420(4)A, β= 99.38(2)°, Z= 2, and R= 0.043. The structure consists of discrete [PdL12] molecules (L1= 6-amino-1,3-dimethyl-5-phenylazouracilate), in which L1 acts as a bidentate ligand through the nitrogen atom of the deprotonated amino group and the nitrogen atom of the azo group bonded to the phenyl ring, to give a square-planar PdN4 geometry with palladium(II) at the inversion centre. The entire molecule is planar with the exception of the phenyl rings which are twisted by 84.4(2)° about the C–N bond away from the co-ordination plane in order to overcome interligand steric crowding. On the basis of i.r. and thermal data a trans-square-planar structure is proposed for (5), the ligand being co-ordinated through the nitrogen atom of the 6-amino group. In the temperature range 230–320 °C this complex eliminates two molecules of HCl to give [PdL52](6). The solid-state parameters and mechanism for this reaction were determined.

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