Abstract
Let L be a three-component link all of whose linking numbers are zero. Write the Alexander polynomial of L as Δ ( x , y , z ) = ( 1 − x ) ( 1 − y ) ( 1 − z ) f ( x , y , z ) \Delta (x,y,z) = (1 - x)(1 - y)(1 - z)f(x,y,z) . Then the integer | f ( 1 , 1 , 1 ) | |f(1,1,1)| is a perfect square.
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