Abstract
A possibility that the 0+ state with the energy of 681.3 keV exists in the 160Dy nucleus is discussed. Calculations based on the interacting vector boson model show that in addition to the known 0+ states with the number of bosons n = 2, 5, 6, and 7 there should exist other states with the number of bosons n = 1, 3, 4, and 8 in 160Dy. It is shown that the peak at the energy 681.3 keV, which we experimentally observed in the 160Dy internal conversion electron spectrum, can be ascribed to the 0+ state with the number of bosons n = 1 or n = 8.
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