Abstract
We calculate the Σ0→Λ0 transition magnetic moment μΣ0Λ0 in the effective quark model with chiral U (3) × U (3) symmetry.5 We find that the dominant contribution is proportional to the quark condensate that indicates the important role of spontaneous breaking of chiral symmetry for its formation. Our result μΣ0Λ0 = -1.62 μN, where μN is a nuclear magneton, agrees well with the experimental data [Formula: see text]. It also agrees well both quantitatively and qualitatively with the result, obtained in the QCD sum rules approach |μΣ0Λ0| = (1.60±0.30)μN,3 where the dominant contribution is proportional to the quark condensate as well.
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