Abstract

Let $(L_n)_{n\geq 0}$ be the Lucas sequence given by $L_0 = 2, L_1 = 1$ and $L_{n+2} = L_{n+1}+L_n$ for $n \geq 0$. In this paper, we are interested in finding all powers of three which are sums of two Lucas numbers, i.e., we study the exponential Diophantine equation $L_n + L_m = 3^{a}$ in nonnegative integers $n, m,$ and $a$. The proof of our main theorem uses lower bounds for linear forms in logarithms, properties of continued fractions, and a version of the Baker-Davenport reduction method in Diophantine approximation.

Highlights

  • We move our interest on the powers of 3 as a sum of two Lucas numbers

  • We are interested in finding all powers of three which are sums of two Lucas numbers, i.e., we study the exponential Diophantine equation Ln + Lm = 3a in nonnegative integers n, m, and a

  • This paper follows the following steps : We first give the generalities on binary linear recurrence, we demonstrate an important inequality on Lucas numbers and determine and reduce a coarse bound by section 3

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Summary

Generalities

We suppose that ak = 0 (otherwise, the sequence {Hn}n≥0 satisfies a recurrence of order less than k). If k = 2, the sequence (Hn)n≥0 is called a binary recurrent sequence. In this case, the characteristic polynomial is of the form f (X) = X2 − a1X − a2 = (X − α1)(X − α2). The binary recurrent sequence {Hn}n≥0 is said to be non degenerated if c1c2α1α2 = 0 and α1/α2 is not a root of unity. Let us define another height, deduced from the last one, called the absolute logarithmic height

Inequalities involving the Lucas numbers
Linear forms in logarithms and continued fractions
Main Results
Reducing of the bound on n
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