Abstract

I am indebted to F. T. Brawn for pointing out that Theorem 2 is incorrect in its generality. In fact, one has to weaken either the hypothesis or the result. An additional hypothesis is more appropriate to the context of the paper: THEOREM 2. If sεSt, v is the measure distribution Δs and ∫ R n × { a } d v = 0 ( a > 0 ) then the mean Ms is continuously differentiate on (0, +∞) and for a > 0 d M s d y ( a ) = − ∫ D a d v (5) The relation (13) obtained in the proof of Theorem 2 is now correct and the proof of Theorem 2 given on p. 543 does not need any alteration.

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