Abstract

Let h be a morphism satisfying h ( a ) = ax for a letter a and a nonempty word x . Then h defines an infinite word (an ω-word) when applied iteratively starting from a . Such ω-words are considered in a binary case. It is shown that only biprefixes can generate cube-free ω-words, i.e. words which do not contain a word υ 3 , with υ ≠ λ, as a subword. The same does not hold true for fourth power-free ω-words, the counterexample being the ω-word defined by the Fibonaccimorphism: h ( a ) = ba , h ( b ) = a . As the main result it is proved that it is decidable whether a given morphism of the above form generates a cube-free ω-word. Moreover, it is shown that no more than 10 steps of iterations are needed to solve the problem.

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