Abstract
We report the $^{63}\mathrm{Cu}$ and $^{65}\mathrm{Cu}$ nuclear spin-lattice relaxation rate measurements of cuprous oxide ${\mathrm{Cu}}_{2}\mathrm{O}$ in a zero field Cu nuclear quadrupole resonance at $T=77--325\phantom{\rule{0.28em}{0ex}}\mathrm{K}$. From the detailed isotopic measurements of the relaxation rates, we successfully estimated a finite magnetic relaxation rate $^{63}W_{M}$ and a predominant nuclear quadrupole relaxation rate $^{63}W_{Q}$. $^{63}W_{Q}$ changed as ${T}^{2.1}$, whereas $^{63}W_{M}$ changed as ${T}^{1.6}$ or ${T}^{\ensuremath{\beta}}\mathrm{exp}(\ensuremath{-}\mathrm{\ensuremath{\Delta}}/\mathit{T})$ with $\ensuremath{\beta}=0.6(3)$ and $\mathrm{\ensuremath{\Delta}}=190(62)\phantom{\rule{0.28em}{0ex}}\mathrm{K}$. The nuclear spin scattering process due to a nondegenerate Fermi gas was discussed as a possible candidate of the magnetic relaxation.
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