Abstract

The nuclear polarization effect in muonic atoms is calculated for $^{208}\mathrm{Pb}$ and $^{40}\mathrm{Ca}$. The nuclear intermediate states of $^{208}\mathrm{Pb}$ are collective particle-hole states calculated from realistic nucleon-nucleon forces. The total effect is an increase of binding of 6.0\ifmmode\pm\else\textpm\fi{}0.6 keV for the $1s$ level, 1.9\ifmmode\pm\else\textpm\fi{}0.2 keV for the $2p$ level, and 1.2\ifmmode\pm\else\textpm\fi{}0.2 keV for the $2s$ level. We are able to set the uncertainties of the calculation at the relatively small values given above for the following reasons: The muonic intermediate states are treated exactly with the reference-spectrum method; the energies of nuclear intermediate states of $l>2$ turn out to be small compared with muonic intermediate state energies; the nuclear dipole states have been well studied experimentally and theoretically; and the nuclear monopole polarization calculated from the particle-hole states has been checked with a Thomas-Fermi theory which gives the observed surface thickness and the surface energy. Similar calculations for $^{40}\mathrm{Ca}$ give the correction to the $1s$ level as 0.2 keV. Henley and Cooper's closure approximation, which leads to a large correction of 58 keV to the $^{208}\mathrm{Pb}$ $1s$ level, is repeated with two of the following improvements: The intermediate muonic states in the continuum are treated properly, and the two-nucleon cross terms in the ground-state nucleus are included. The correction then comes down to 6 keV.

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