Abstract

The mol­ecule of the title compound, PhNHC(=S)C(=O)NHPh or C14H12N2OS, consists of two planar fragments, one of which includes the central NHC(=S)C(=O)NH chain together with the Ph substituent on the C=O side; the second Ph ring, the one on the C=S side, all by itself, makes up the second planar fragment. Its plane is twisted about the N—C bond by 52.87 (9)° with respect to the plane of the first fragment. The C=S and C=O double bonds adopt the transoid conformation with the torsion angle S=C—C=O equal to −179.6 (2)°. The mol­ecules in the crystal are linked into centrosymmetric dimers due to the N—H⋯O hydrogen bond involving the thio­amide NH group.

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