Abstract

We continue the work of the previous paper (Hachenberger,Finite Fields Appl., in press), and, generalizing some of the results obtained there, we give explicit constructions of free and completely free elements in GF(qrn) over GF(q), wherenis any nonnegative integer and whereris any odd prime number which does not divide the characteristic of GF(q) or wherer= 2 andq≡ 1 mod 4. Together with results on the case wherer= 2 andq≡ 3 mod 4 obtained in the previous paper and results on the well-known case whereris equal to the characteristic of GF(q), we are able to explicitly determine free and completely free elements in GF(qm) over GF(q) for every nonnegative integermand every prime powerq.

Talk to us

Join us for a 30 min session where you can share your feedback and ask us any queries you have

Schedule a call

Disclaimer: All third-party content on this website/platform is and will remain the property of their respective owners and is provided on "as is" basis without any warranties, express or implied. Use of third-party content does not indicate any affiliation, sponsorship with or endorsement by them. Any references to third-party content is to identify the corresponding services and shall be considered fair use under The CopyrightLaw.