Abstract

We point out that the decay mode ${D}^{0}\ensuremath{\rightarrow}{K}^{0}{K}^{0}$ has no factorizable contribution. In chiral perturbation language, treating ${D}^{0}$ as heavy, the $\mathcal{O}(p)$ contribution is zero. We calculate the nonfactorizable chiral loop contributions of order $\mathcal{O}{(p}^{3}).$ Then, we use a heavy-light type chiral quark model to calculate nonfactorizable tree level terms, also of order $\mathcal{O}{(p}^{3}),$ proportional to the gluon condensate. A priori, chiral loops are not expected to give good precision because the energy release in this decay is almost 800 MeV. Still, we find that both the chiral loops and the gluon condensate contributions are of the same order of magnitude as the experimental amplitude.

Talk to us

Join us for a 30 min session where you can share your feedback and ask us any queries you have

Schedule a call

Disclaimer: All third-party content on this website/platform is and will remain the property of their respective owners and is provided on "as is" basis without any warranties, express or implied. Use of third-party content does not indicate any affiliation, sponsorship with or endorsement by them. Any references to third-party content is to identify the corresponding services and shall be considered fair use under The CopyrightLaw.