Abstract
The \ensuremath{\alpha}-cluster structure of the $^{18}\mathrm{O}$ nucleus is investigated by studying the properties of a global optical model potential which describes $^{14}\mathrm{C}$(\ensuremath{\alpha},\ensuremath{\alpha}) elastic scattering at 28, 40, and 54 MeV on the whole angular range. This calculation does not support the existence of the negative-parity molecular dipole states which have been proposed to coexist with the positive-parity four-particle--two-hole (4p-2h) deformed band built on the ${\mathit{J}}^{\mathrm{\ensuremath{\pi}}}$=${0}^{+}$, ${\mathit{E}}_{\mathit{x}}$=3.63 MeV state. It suggests that the broad ${\mathit{J}}^{\mathrm{\ensuremath{\pi}}}$=${1}^{\mathrm{\ensuremath{-}}}$ state recently seen around ${\mathit{E}}_{\mathit{x}}$=9 MeV in the \ensuremath{\beta}-delayed \ensuremath{\alpha}-particle spectrum from $^{18}\mathrm{N}$ is the bandhead of the negative-parity inversion-doublet partner band of the 4p-2h band.
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