Abstract

In the title compound, C11H12N2O5, the conformation of the N—H bond in the amide segment is syn to the ortho-nitro group in the benzene ring. The amide C=O and the carboxyl C=O of the acid segment are syn to each other and both are anti to the H atoms on the adjacent –CH2 groups. Furthermore, the C=O and O—H bonds of the acid group are in syn positions with respect to each other. The dihedral angle between the benzene ring and the amide group is 36.1 (1)°. The amide H atom shows bifurcated intra­molecular hydrogen bonding with an O atom of the ortho-nitro group and an inter­molecular hydrogen bond with the carbonyl O atom of another mol­ecule. In the crystal, the N—H⋯O(C) hydrogen bonds generate a chain running along the [100] direction. Inversion dimers are formed via a pair of O—H⋯O(C) interactions, that form an eight-membered hydrogen-bonded ring involving the carboxyl group.

Highlights

  • N—H bond in the amide segment is syn to the ortho-nitro group in the benzene ring

  • C O of the acid segment are syn to each other and both are anti to the H atoms on the adjacent –CH2 groups

  • The C O and O—H bonds of the acid group are in syn positions with respect to each other

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Summary

CCD detector

N—H bond in the amide segment is syn to the ortho-nitro group in the benzene ring. C O of the acid segment are syn to each other and both are anti to the H atoms on the adjacent –CH2 groups. The C O and O—H bonds of the acid group are in syn positions with respect to each other. The dihedral angle between the benzene ring and the amide group is. The amide H atom shows bifurcated intramolecular hydrogen bonding with an O atom of the ortho-nitro group and an intermolecular hydrogen bond with the carbonyl O atom of another molecule. H O(C) interactions, that form an eight-membered hydrogen-bonded ring involving the carboxyl group

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