Abstract

The interest in SnTe has recently increased due to its topological crystalline insulator nature, despite the fact that SnTe is always heavily $p$ type. Here, using first-principles calculations, we identify the microscopic origin of the $p$-type conductivity of SnTe. It is found that the negatively charged Sn vacancy (${V}_{\mathrm{Sn}}^{2\ensuremath{-}}$) dominates the electronic properties of SnTe: regardless of the growth conditions, ${V}_{\mathrm{Sn}}^{2\ensuremath{-}}$ always has a negative formation energy within the band gap, which forces the Fermi level below the valence band maximum (VBM), leading to degenerate $p$-type doping. In contrast, the deeper VBM of PbTe increases the formation energy of the Pb vacancy (${V}_{\mathrm{Pb}}^{2\ensuremath{-}}$), allowing for either $n$-type or $p$-type PbTe. So even though standard n doping of SnTe is very difficult, alloying with Pb can achieve $n$ doping by lowering the VBM, thereby inhibiting the formation of cation vacancy and, thus, probably producing a topological crystalline insulator with the Fermi level located near the Dirac point.

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