Abstract

The luminescence properties of LaPO 4:Tb 3+,Me 3+ (Me = Gd, Bi, Ce) were investigated under VUV excitation. The results indicate that only Gd 3+ plays an intermediate role in energy transfer from the host absorption band to Tb 3+ under 147 nm excitation, Bi 3+ and Ce 3+ have no contribution to improving the emission intensity of La 0.95PO 4:Tb 0.05 3+ because the charge transfer band of Bi 3+ is mismatching for the excitation wavelength (147 nm) and Ce 3+ can be oxidized easily. A new band at 135 nm is observed in the excitation spectrum of La 0.92PO 4:Tb 0.05 3+,Bi 0.03 3+, which may correlate with the absorption of Bi 2+.

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