Abstract
Abstract— The lumiflavin‐sensitized photooxygenation of indole in aqueous solutions has been investigated by means of steady light photolysis and flash photolysis. The semiquinone of lumiflavin and the half‐oxidized radical of indole were formed by the reaction between triplet lumiflavin and indole (3.7 times 109M‐1 s‐1). The semiquinone anion radical of lumiflavin reacted with oxygen to form superoxide radical. The triplet state of lumiflavin also reacted with oxygen forming singlet oxygen, 1O2. But the reaction between 1O2 and indole (7 times 107 M_l s_1; estimated from steady light photolysis using Rose Bengal as a sensitizer) was far less efficient than the reaction between indole and triplet lumiflavin. The quantum yield of the lumiflavin‐sensitized photooxygenation of dilute indole via radical processes was much higher than that via1O2 processes, though appreciable 1O2 was formed.
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