Abstract
A very simple model is applied to the first four negative-parity states of $^{12}\mathrm{Be}$. Energies of the corresponding four states in $^{14}\mathrm{C}$ are used to validate the model and to determine the doublet splitting parameters. Predictions for $^{12}\mathrm{Be}$ are in remarkable agreement with excitation energies of the known 1${}^{\ensuremath{-}}$ at 2.70 MeV and the suspected (3${}^{\ensuremath{-}}$) at 4.56 MeV. Predicted excitation energies of 0${}^{\ensuremath{-}}$ and 2${}^{\ensuremath{-}}$ are 3.59 and 5.12 MeV, respectively.
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