Abstract

The mean lifetime of the first excited state of B12 at 0.95 MeV was measured by the Doppler shift attenuation technique using the ${\mathrm{B}}^{11}(d, p){\mathrm{B}}^{12}$ reaction to populate the state. The result is $\ensuremath{\tau}=(3.4\ifmmode\pm\else\textpm\fi{}1)\ifmmode\times\else\texttimes\fi{}{10}^{\ensuremath{-}13}$ sec. Sum rules are invoked to show that the deexcitation of this state to the ${J}^{\ensuremath{\pi}}={1}^{+}$ ${\mathrm{B}}^{12}$ ground state cannot be predominantly $E2$ so that the spin parity of the ${\mathrm{B}}^{12}$ first excited state cannot be ${3}^{+}$. The angular distribution of the ground-state decay from this level was measured at a deuteron energy of 0.8 MeV. The result rules out a zero-spin assignment. It is concluded that the available experimental evidence indicates ${2}^{+}$ for the spin parity of the ${\mathrm{B}}^{12}$ first excited state.

Full Text
Paper version not known

Talk to us

Join us for a 30 min session where you can share your feedback and ask us any queries you have

Schedule a call

Disclaimer: All third-party content on this website/platform is and will remain the property of their respective owners and is provided on "as is" basis without any warranties, express or implied. Use of third-party content does not indicate any affiliation, sponsorship with or endorsement by them. Any references to third-party content is to identify the corresponding services and shall be considered fair use under The CopyrightLaw.