Abstract
A novel green emitting phosphor,Ba2B2P2O10∶Eu2+,is prepared by solid state method,and its luminescent characteristics are investigated.BaCO3,H3BO3,NH4H2PO4 and Eu2O3 were used as starting materials.After these individual materials were blended and grounded thoroughly in an agate mortar,the homogeneous mixture was heated at 1 000 ℃ for 5 h in a reduce atmosphere(5:95(H2/N2)),and the phosphor were obtained.The phase present of the samples was characterized by powder X-ray diffraction(XRD).The spectral characteristics of the phosphors were measured by a SHIMADZU RF-540 fluorescence spectrophotometer.Ba2B2P2O10∶Eu2+ shows a one dissymmetrical band at 522 nm,and the excitation spectrum for 522 nm emission extends from 300 to 450 nm,and the highest peak locates at 381 nm.The crystallographic sites of Eu2+ in Ba2B2P2O10 were calculated by van Uitert formula.The result shows that 507 nm emission band originates from the eight sites of Eu2+,and that 542 nm emission band comes of the six sites of Eu2+.The effect of Eu2+ content on the emission intensity of Ba2B2P2O10∶Eu2+ phosphor was investigated,the result shows that the emission intensity of the phosphor increases with increasing Eu2+ concentration,then decreases,viz.,the concentration quenching exists,and the Eu2+ concentration corresponding to the maximal emission intensity is 3 mol%.And the concentration quenching mechanism is the d-d interaction.
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