Abstract

Sn only by a permutation of its rows and columns, then G is isomorphic to Sn. In this paper we consider a question naturally raised by Nagao’s result. To state it, we must recall that the ordinary irreducible characters of Sn are canonically labelled by the partitions of n, and that this set also labels the conjugacy classes of Sn. Given partitions and of n, let ( ) be the value of the irreducible character of Sn labelled by on elements of cycle type . Now suppose that one has discovered (for example, by applying Nagao’s theorem) that a given square matrix is an unlabelled character table of the symmetric group Sn. We ask: when can one go further, and uniquely reconstruct the partitions labelling its rows and columns? The answer is

Full Text
Paper version not known

Talk to us

Join us for a 30 min session where you can share your feedback and ask us any queries you have

Schedule a call

Disclaimer: All third-party content on this website/platform is and will remain the property of their respective owners and is provided on "as is" basis without any warranties, express or implied. Use of third-party content does not indicate any affiliation, sponsorship with or endorsement by them. Any references to third-party content is to identify the corresponding services and shall be considered fair use under The CopyrightLaw.