Abstract
The chlorination of naphthalene shows an inverse deuterium isotope effect, the reaction of naphthalene being slower than that of octadeuterionaphthalene by a factor of 0.85. The product-forming stages are also subject to a deuterium isotope effect which influences the partitioning between addition and substitution; the most direct interpretation of the results is that the values of kH/kD for the stages of proton-loss are subject to a normal deuterium isotope effect, with kH/kD ⦔ 1.4.
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