Abstract

It has been found that high-order deformation (e.g. β6) can have important effects on the structures of superheavy nuclei. In the present work, we investigate octupole deformation effects on superheavy nuclei with an improved potential-energy-surface (PES) calculation by including reflection-asymmetric deformations in a space of (β2, β3, β4, β5). The calculations give various deformations including highly deformed (β2 ≈ 0.4) and superdeformed (β2 ≈ 0.7) shapes. The octupole-deformation degree of freedom mainly affects the fission barrier beyond the second minimum of PES.

Highlights

  • It has been found that high-order deformation (e.g. β6) can have important effects on the structures of superheavy nuclei

  • We investigate octupole deformation effects on superheavy nuclei with an improved potential-energy-surface (PES) calculation by including reflection-asymmetric deformations in a space of (β2, β3, β4, β5)

  • Octupole correlation manifests itself in atomic nuclei usually with enhanced E1 transitions connecting interleaved positive and negative-parity bands, which is similar to the rotational bands observed in reflectionasymmetric molecules [1]

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Summary

The model

The total potential energy, which is calculated as a function of shape, proton number Z, and neutron number N, is the sum of a macroscopic term and a microscopic term representing the shell correction [22, 23]. The macroscopic term changes smoothly as a function of particle number and deformation. The microscopic term can have rapid fluctuation with changing deformation and particle number. K k k where vk, ek, Δ and λ2 represent the occupation probabilities, single-particle energies, pairing gap and number-fluctuation constant, respectively. The shell correction energy is calculated by δEshell = ELN − EStrut, where EStrut is obtained by the Strutinsky method [31, 32] with a smoothing range γ = 1.20 ω0 ( ω0 = 41/A1/3 MeV), and a correction polynomial of order p = 6. PES is obtained in the multi-dimensional deformation space (β2, β3, β4, β5) and the nuclear equilibrium deformation is determined by minimizing the PES

Calculations and discussions
Conclusions
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