Abstract
When a solution of Cp(Ph3P)Ru{SiMe2···O(Me)···SiMe2} (1; Cp = η5-C5H5) and a two-electron-donating ligand L was heated at 130 °C, a CH bond of a phenyl group was activated by the RuSi double bond, and the complexes CpLRuSiMe2(o-C6H4PPh2) (2a, L = PPh3; 2b, L = PMe3; 2c, L = PEt3; 2d, L = P(OMe)3; 2e, L = tBuNC) were obtained. Heating 1 in the absence of a ligand at 130 °C gave CpRuSiMe2(o-C6H4PPh2)(H)(SiMe2OMe) (3).
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