Abstract

AbstractA set-theoretical solution of the pentagon equation on a non-empty set X is a function $$s:X\times X\rightarrow X\times X$$ s : X × X → X × X satisfying the relation $$s_{23}\, s_{13}\, s_{12}=s_{12}\, s_{23}$$ s 23 s 13 s 12 = s 12 s 23 , with $$s_{12}=s\times \,{{\,\textrm{id}\,}}_X$$ s 12 = s × id X , $$s_{23}={{\,\textrm{id}\,}}_X \times \, s$$ s 23 = id X × s and $$s_{13}=({{\,\textrm{id}\,}}_X\times \, \tau )s_{12}({{\,\textrm{id}\,}}_X\times \,\tau )$$ s 13 = ( id X × τ ) s 12 ( id X × τ ) , where $$\tau :X\times X\rightarrow X\times X$$ τ : X × X → X × X is the flip map given by $$\tau (x,y)=(y,x)$$ τ ( x , y ) = ( y , x ) , for all $$x,y\in X$$ x , y ∈ X . Writing a solution as $$s(x,y)=(xy,\theta _x(y))$$ s ( x , y ) = ( x y , θ x ( y ) ) , where $$\theta _x: X \rightarrow X$$ θ x : X → X is a map, for every $$x\in X$$ x ∈ X , one has that X is a semigroup. In this paper, we study idempotent solutions, i.e., $$s^2=s$$ s 2 = s , by showing that the idempotents of X have a crucial role in such an investigation. In particular, we describe all such solutions on monoids having central idempotents. Moreover, we focus on idempotent solutions defined on monoids for which the map $$\theta _1$$ θ 1 is a monoid homomorphism.

Talk to us

Join us for a 30 min session where you can share your feedback and ask us any queries you have

Schedule a call

Disclaimer: All third-party content on this website/platform is and will remain the property of their respective owners and is provided on "as is" basis without any warranties, express or implied. Use of third-party content does not indicate any affiliation, sponsorship with or endorsement by them. Any references to third-party content is to identify the corresponding services and shall be considered fair use under The CopyrightLaw.