Abstract

We study the global behavior of the ground state energy for the nonlinear scalar field equation (including the $p$-Laplacian version), and give a complete description of this energy in terms of nonlinearity power. More precisely,let$\mathcal{E}_{\lambda,q}(u)=\frac{1}{p}(\|\nabla~u\|_p^p+\lambda\|u\|_p^p)-\frac{1}{q}\|u\|_q^q$ bethe energy functional in $~W^{1,p}(\mathbb{R}^N)$,where $\lambda>0$, $1<p<N$, $p<q<p^*:=\frac{pN}{N-p}$, and $p^*$ is the critical Sobolev exponent. It is known that $\mathcal{E}_{\lambda,q}(u)$ has a unique radially symmetric mountain-pass critical point $U_{\lambda,q}$, which is called the ground state 解 to the corresponding nonlinear scalar field equation and whose energy $\mathcal{E}_{\lambda,q}(U_{\lambda,q})$ is called the ground state energy $\mathfrak{m}(\lambda,q)$.We show that there is a decreasing function $\lambda_0(q)$ defined in $q\in~[p,p^*]$ with $\lambda_0(p)=1~$ and $\lambda_0(p^*)=0$such that $\mathfrak{m}(\lambda,r)$ is strictly increasing for $r\in(p,~q)$ with $\lambda\in(0,~\lambda_0(q))$ being fixed, $\mathfrak{m}(\lambda,r)$ is strictly decreasing for $r\in(q,~p^*)$ with $\lambda\in(\lambda_0(q),~1)$ being fixed, and $\mathfrak{m}(\lambda,r)$ is strictly decreasing for all $r\in(p,~p^*)$ with $\lambda\in[1,~+\infty)$ being fixed.We also deduce the precise asymptotic behavior of $\lambda_0(q)$ as $q\to~p$ and $q\to~p^*$. This is done by establishing a relation between power-law scalar fieldequations and logarithmic-law scalar field equations,which is of the independent interest.

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