Abstract

The usual set of autosomal markers (A-STRs) available in commercial kits is often insufficient to discriminate between close relationships when only two subjects are available for analysis. X-chromosome markers (X-STRs) provide higher statistical power in special cases. Formulas are derived for the probabilities of all possible genotype pairs for X-STRs of any sex combination for seven common relationships. The power of exclusion (PE) of X-STRs in parentage analysis is compared with that of A-STRs of equivalent distribution of allele frequency. Seventy-three equations were obtained, from which the likelihood ratio of any two alternative hypotheses about the relationship between two individuals can be obtained by division and simplification. For father-daughter and mother-son duos, the PE of X-STRs is almost twice the corresponding value of A-STRs for moderately low values of heterozygosity (0.6-0.75); for alleged pairs of sisters and pairs of half-sisters the PE is equivalent to that of A-STRs in parent-child duos. Considering four real unlinked X-STRs, the cumulative PE for father-daughter and mother-son duos was 99 percent, compared with 94 percent if they were autosomal. X-STRs can substantially increase the discrimination capacity of standard A-STRs in parentage analyses involving pairs of individuals. Up to four unlinked X-STRs may be treated as independent loci. When linked loci are included, computer programs that calculate pedigree likelihoods can be used.

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