Abstract
Among other results, we have provided general singular value inequality as follows:Let X1,X2,Y1, and Y2 be positive bounded linear operators on a complex separable Hilbert space. Then2sj(X11/2Y11/2−X21/2Y21/2)≤sj(S⊕T) for j=1,2,..., where S=X1+Y1+|X21/2X11/2−Y21/2Y11/2|, and T=X2+Y2+|X11/2X21/2−Y11/2Y21/2|. In particular,sj(X1−X2)≤sj(X1⊕X2) for j=1,2,... Moreover, we have proven several singular value inequalities generalizing the previous inequalities.
Talk to us
Join us for a 30 min session where you can share your feedback and ask us any queries you have
Schedule a callDisclaimer: All third-party content on this website/platform is and will remain the property of their respective owners and is provided on "as is" basis without any warranties, express or implied. Use of third-party content does not indicate any affiliation, sponsorship with or endorsement by them. Any references to third-party content is to identify the corresponding services and shall be considered fair use under The CopyrightLaw.
