Abstract
We propose a new process which probes the BFKL dynamics in the high energy proton-proton scattering, namely the forward Drell-Yan (DY) production accompanied by a backward jet, separated from the DY lepton pair by a large rapidity interval. The proposed process probes higher rapidity differences and smaller transverse momenta than in the Mueller-Navelet jet production. It also offers a possibility of measuring new observables like lepton angular distribution coefficients in the DY lepton pair plus jet production.
Highlights
A classical probe of QCD radiation in the BFKL approach applied to hadronic collisions was proposed by Mueller and Navelet (MN) [6] to study hadroproduction of two jets with similar transverse momenta but separated by a large rapidity interval ∆Y which are produced from a collision of two partons with moderate hadron momentum fractions
We propose a new process which probes the BFKL dynamics in the high energy proton-proton scattering, namely the forward Drell-Yan (DY) production accompanied by a backward jet, separated from the DY lepton pair by a large rapidity interval
A substantial theoretical progress has been made since the appearance of the initial papers to include the next-to-leading order (NLO) corrections to the jet impact factors and the next-to-leading-logarithmic (NLL) corrections to the BFKL evolution kernel to make a successful comparison with data
Summary
The schematic diagram of the Drell-Yan + jet process is show in figure 1. Defining rapidity difference between photon and jet,. In analogy to the Mueller-Navelet (MN) process [16], we define the rapidity difference between the measured jet and the separated in rapidity the photon plus quark system. Where xg is the momentum fraction of the uppermost gluon in the BFKL ladder, see figure 1, which value is fixed by kinematics. This rapidity difference is an argument of the BFKL kernel, discussed, while ∆YγJ is a measurable quantity. Taking into account that at the jet vertex the transverse momentum of the initial partons equals zero, we have k2⊥ = −pJ⊥.
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