Abstract
Abstract Previously1 we have observed a 19 NMR asymmetric line in polycrystalline ThF4 in the 6–9 kOe fields, which was ascribed to the anisotropy of the 19F nuclei screening constant. However, the accepted interpretation in the case of a powder sample is not the only possible one, since in the presence of chemically or structurally non-equivalent fluorine atom groups spectrum asymmetry may also arise on account of the difference in the nuclei magnetic screening constants due to non-equivalent positions. This dilemma in the case of polycrystalline samples may be solved only when recording spectra in the highest fields. Non-equivalence of the nuclei may lead, to a split of the NMR spectrum into components, corresponding to the various positions. When spectrum asymmetry is due to the anisotropy of the screening constant, field strength rise may but lead to an increase of the total spectrum width, its shape remaining unaltered.
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