Abstract

The main purpose of this paper is to prove the existence of positive solutions for a system of nonlinear Caputo-type fractional differential equations with two parameters. By using the Guo–Krasnosel’skii fixed point theorem, some existence theorems of positive solutions are obtained in terms of different values of parameters. Two examples are given to illustrate the main results.

Highlights

  • Fractional-order calculus, which is an important branch of mathematics, was introduced in 1695

  • Boundary value problems of fractional differential equations have appeared with applications of fractional-order calculus; so far, there have been many literature works about boundary value problems of fractional differential equations

  • In [10], the authors used the Guo–Krasnosel’skii fixed point theorem and the Leggett–Williams fixed point theorem to obtain the existence of positive solutions to the nonlinear Caputo fractional q-difference equation with integral boundary conditions

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Summary

Introduction

Fractional-order calculus, which is an important branch of mathematics, was introduced in 1695. In [10], the authors used the Guo–Krasnosel’skii fixed point theorem and the Leggett–Williams fixed point theorem to obtain the existence of positive solutions to the nonlinear Caputo fractional q-difference equation with integral boundary conditions. In [23], the authors investigated a coupled system of Caputo fractional differential equations with coupled non-conjugate Riemann–Stieltjes type integro-multipoint boundary conditions They obtained some new theorems by using the Leray–Schauder nonlinear alternative, the Krasnosel’skii fixed point theorem, and Banach’s contraction mapping principle. In [26, 27], the authors used the Guo–Krasnosel’skii fixed point theorem to investigate the existence of positive solutions for systems of fractional differential equations nonlocal boundary value problems with two parameters, and the existence of positive solutions were obtained.

Caputo fractional differential equation
We define the cone
From and
Then we have
Then we get
We can get

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